Rainbow Salt Investigation in Density
Purpose : To make various saline solutions and layer them according to their respective densities.
Materials :
Method:
Prepare each solution by adding salt, water, and food coloring.
Calculations : To find the density of each solution layer ;
Example : Solution #1
Mass = 16.0 g of salt + 60 g of water = 76.0 g of solution
Volume = 60 mL of water
Density= Mass/ Volume = 76.0 g/ 60 mL = 1.27 g/mL
Conclusion
Materials :
- 1-100 mL Graduated Cylinder
- 2-150 mL Beakers
- Pipette
- Sheet of Background paper , white
- Salt
- Water
Method:
Prepare each solution by adding salt, water, and food coloring.
Calculations : To find the density of each solution layer ;
Example : Solution #1
Mass = 16.0 g of salt + 60 g of water = 76.0 g of solution
Volume = 60 mL of water
Density= Mass/ Volume = 76.0 g/ 60 mL = 1.27 g/mL
Conclusion
- If all solutions were made with just salt and water, why did they form different layers ? Because of density, when theres more salt theres more dense is that solution. the more dense layer stays at the bottom, meanwhile the one that doesn't have any salt stay at the surface of the water.
- The ocean contains water with different salinities. Where do you think the saltiest layers would be found? Why? The saltiest layer will be found at the very bottom of the ocean, because the more dense, the more heavy the water gets.. and the dense stays at the bottom.
- What happens to density as temperature changes? The density can change to highest to lowest.
- Where in the ocean water column would you except to find warm, fresh water? Where could you find colder, saltier water? fresh water could possibly be at the surfac of the ocean of the ocean Because by its less salinity which means its less dense, with less salinity a water is more warm or fresh and stays at the top. On the other hand, very salty water is dense and colder so you'll find that at the bottom of the water.